修复sql问题

job_one_game.py

@@ -1,6 +1,6 @@
 from utils.read_sql_files import read_one_game_sql_files
 from utils.execute_sql import select_execute_sql
-
+from utils.read_sql_files import read_sql_files
 
 
 def dim(game_information):
@@ -21,8 +21,7 @@ def ads(game_information):
     read_one_game_sql_files('ads', game_information)
 
 
-if __name__ == '__main__':
-
+def job_one_game():
     sql_params = "49,50,51"
 
     sql_str = f"select relation_id,game_channel_id,game_identity,game_platform_id from dim.game_product_relation where relation_id IN ({sql_params})"
@@ -39,3 +38,19 @@ if __name__ == '__main__':
         # dwd(game_information_dic)
         # dws(game_information_dic)
         # ads(game_information_dic)
+
+
+def rerun():
+    # read_sql_files('dim')
+
+    read_sql_files('dwd_before')
+    read_sql_files('dwd_after')
+
+    read_sql_files('dws_before')
+    read_sql_files('dws_after')
+
+    read_sql_files('ads')
+
+
+if __name__ == '__main__':
+    rerun()

job_test.py

@@ -29,6 +29,8 @@ def read_sql_files(directory, day):
         log.error(f"读取文件 {directory} 时出现错误: {e}")
 
 
+
+
 if __name__ == '__main__':
     # 遍历300到0
     for day in range(301):

sql/ads/order_ltv.sql

@@ -9,7 +9,7 @@ SELECT
     t1.ds,
     COUNT(DISTINCT t1.user_id) AS num,
     COALESCE(SUM(pay_amount),0)  order_amount,
-    SUM(CASE WHEN (t2.ds_date-t1.ds_date) <= 0 THEN pay_amount ELSE 0 END) AS ltv0,
+    SUM(CASE WHEN t2.ds_date=t1.ds_date THEN pay_amount ELSE 0 END) AS ltv0,
     SUM(CASE WHEN (t2.ds_date-t1.ds_date) <= 1 THEN pay_amount ELSE 0 END) AS ltv1,
     SUM(CASE WHEN (t2.ds_date-t1.ds_date) <= 2 THEN pay_amount ELSE 0 END) AS ltv2,
     SUM(CASE WHEN (t2.ds_date-t1.ds_date) <= 3 THEN pay_amount ELSE 0 END) AS ltv3,
@@ -30,7 +30,7 @@ LEFT JOIN
 ON
 t1.relation_id = t2.relation_id
 AND t1.user_id = t2.user_id
-AND t2.ds_date-t1.ds_date IN (1,2,3,4,5,6,7,14,30,60,90,150,300)
+AND t2.ds_date-t1.ds_date IN (0,1,2,3,4,5,6,7,14,30,60,90,150,300)
 where t1.ds>='${300_days_later}'
 GROUP BY
     t1.relation_id, t1.prodid, t1.ds

sql/dim/first_user.sql

@@ -1,33 +1,5 @@
 -- 取登陆最早时间 逻辑:如果之前没出现过,那插入这条记录做最早用户登陆时间
 -- 首次写入数据sql
--- INSERT INTO dim.first_user(game_channel_id,game_identity,game_platform_id,relation_id,prodid,user_id,ds,ds_date)
--- WITH active_account_tmp AS (
---   SELECT distinct
---     t1.channel_id,
---     t1.game_identity,
---     t1.platform_id,
---     t1.user_id,
---     '${bizdate}' AS ds  -- 直接赋值替代min(ds)
---   FROM ods.active_account_list t1
---   WHERE t1.ds = '${bizdate}'
--- )
--- SELECT t2.game_channel_id
---         ,t2.game_identity
---         ,t2.game_platform_id
---         ,t2.relation_id
---         ,t2.product_id prodid
---         ,t1.user_id
---         ,t1.ds ds
---         ,'${biz-date}' ds_date
--- FROM    active_account_tmp t1
--- inner join
--- dim.game_product_relation t2
--- ON      t1.channel_id = t2.game_channel_id
--- AND     t1.game_identity = t2.game_identity
--- AND     t1.platform_id = t2.game_platform_id
--- ON CONFLICT (relation_id, user_id)
--- DO NOTHING;
-
 INSERT INTO dim.first_user(game_channel_id,game_identity,game_platform_id,relation_id,prodid,user_id,ds,ds_date)
 WITH active_account_tmp AS (
   SELECT distinct